1、答案：D D. 0.56
解析：两步转移概率为 (P2)2,3(P^2)_{2,3}(P2)2,3=∑k=13P2kPk3\sum_{k=1}^3 P_{2k}P_{k3}∑k=13P2kPk3。 给定
则 (P2)2,3(P^2)_{2,3}(P2)2,3=0⋅0+0.2⋅0.8+0.8⋅0.50\cdot0+0.2\cdot0.8+0.8\cdot0.50⋅0+0.2⋅0.8+0.8⋅0.5=0.16+0.400.16+0.400.16+0.40=0.560.560.56。
1、一个三状态马尔科夫链的转移矩阵为 [0.10.9000.20.80.500.5]\left[\begin{array}{ccc}0.1 & 0.9 & 0 \\0 & 0.2 & 0.8 \\0.5 & 0 & 0.5\end{array}\right]0.100.50.90.2000.80.5 从状态2出发，两步到达状态3的概率是() {{ select(1) }}
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